A) 250V
B) 300V
C) 400V
D) 600V
Correct Answer: C
Solution :
Law of conservation of charge \[{{\operatorname{Q}}_{1}}+{{Q}_{2}}=Q\] \[{{\operatorname{C}}_{1}}{{V}_{1}}+{{\operatorname{C}}_{2}}{{V}_{2}}=\left( {{\operatorname{C}}_{1}}+{{C}_{2}} \right){{\operatorname{V}}_{common}}\] \[20\times 500+10\times 200=\left( 20+10 \right){{V}_{e}}\] \[30{{V}_{e}} = 12000\] \[{{\operatorname{V}}_{e}}=400V\]You need to login to perform this action.
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