A) Butanol-1
B) Butanol-2
C) 2 - Butanone
D) Butanol
Correct Answer: C
Solution :
(2-Butanone) \[\begin{align} & \,\,\,\,\,\,\,\,\,\,\,\,\left( 2-Butyne \right) \\ & {{\operatorname{CH}}_{3}}-C\equiv C-C{{H}_{3}}+{{H}_{2}}O \xrightarrow{{{H}_{2}}S{{O}_{4}}/HgS{{O}_{4}}} \\ \end{align}\] \[\overset{1}{\mathop{\operatorname{C}}}\,{{H}_{3}}\overset{2}{\mathop{C}}\,O\overset{3}{\mathop{C}}\,{{H}_{2}}\overset{4}{\mathop{C}}\,{{H}_{3}}\] (2-Butanone)You need to login to perform this action.
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