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NEET Sample Paper NEET Sample Test Paper-47

  • question_answer
    Two cells of \[\operatorname{emf} {{E}_{1}} and {{E}_{2}} \left( {{E}_{1}}> {{E}_{2}} \right)\]are connected as shown in figure. When a potentiometer is connected between A and B, then the balancing length of the potentiometer wire is 300cm. On connecting the same potentiometer between A and C, the balancing length is 100cm. The ratio\[\frac{{{\operatorname{E}}_{1}}}{{{\operatorname{E}}_{2}}}\] is:                                              

    A) 3:1                   

    B) 1:3   

    C) 2:3                               

    D) 3:2

    Correct Answer: D

    Solution :

    \[{{\operatorname{V}}_{AB}}={{E}_{1}}=k=300\] \[{{\operatorname{V}}_{AC}}={{E}_{1}}-{{E}_{2}}=k\times 100\] By (1) and (2) \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{3}{2}\]


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