A) 1 m/s
B) 10 m/s
C) 8 m/s
D) 3 m/s
Correct Answer: C
Solution :
\[{{\operatorname{V}}_{y}}={{u}_{y}}+gt\] \[{{\operatorname{V}}_{y}}=gt{{u}_{y}}=0\] \[{{\operatorname{V}}_{y}}=10\times 0.7\operatorname{m}/s\] \[\operatorname{V}=\sqrt{{{V}_{x}}^{2}+{{V}_{y}}^{2}}\] \[\sqrt{{{7}^{2}}+{{4}^{2}}}\] \[\sqrt{65}\] \[=8m/s\]You need to login to perform this action.
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