A) \[{{\operatorname{SbF}}_{3}}\]
B) \[{{\operatorname{MnF}}_{3}}\]
C) \[{{\operatorname{kSbF}}_{6}}\]
D) \[{{\operatorname{MnF}}_{5}}\]
Correct Answer: A
Solution :
\[{{\operatorname{SbF}}_{5}}\] As the following reaction: \[2{{K}_{2}}{{M}_{n}}{{F}_{6}}+ 4Sb{{F}_{5}}\to 4KSb{{F}_{6}}+Mn{{F}_{3}}+ {{F}_{2}}\]You need to login to perform this action.
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