A) R
B) \[\frac{3R}{2}\]
C) \[\frac{5R}{2}\]
D) 2R
Correct Answer: A
Solution :
\[{{\operatorname{PV}}^{3}} = constant\] \[\operatorname{C}={{C}_{v}}+\frac{R}{1-x}\] \[\operatorname{x}=3\] \[\operatorname{C}=\frac{3}{2}R+\frac{R}{1-3}\therefore {{\operatorname{C}}_{v}}=\frac{3}{2}R\] for monoatomic \[\operatorname{C}=\frac{3R}{2}-\frac{R}{2}\] \[\operatorname{C}=R\]You need to login to perform this action.
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