A) 2
B) 2.5
C) 1.6
D) 1.5
Correct Answer: D
Solution :
Assume 'x' be the real depth from one side \[\mu =\frac{\operatorname{x}}{6}=\frac{15-\operatorname{x}}{4}\] \[\operatorname{x}=9\] \[\mu =\frac{\operatorname{x}}{6}=\frac{9}{6}\] \[\mu =1.5\]You need to login to perform this action.
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