NEET Sample Paper NEET Sample Test Paper-48

  • question_answer
    The masses of the wires of copper are in the ratio 5 : 3 : 1 and their lengths are in the ratio 1:3:5. The ratio of their electrical resistances is:

    A) 5:3:1                            

    B) \[\sqrt{125}:15:1\]

    C) 1:15:125                       

    D) 1:3:5

    Correct Answer: B

    Solution :

    \[\operatorname{R}=\frac{\rho \ell }{\operatorname{A}}\frac{\ell }{\ell }=\frac{\rho {{\ell }^{2}}}{\operatorname{V}}\frac{\rho }{\rho }=\frac{{{\rho }^{2}}{{\ell }^{2}}}{\operatorname{m}}\] (volume=Area length) \[{{\operatorname{R}}_{1}}:{{R}_{2}}:{{R}_{3}}=\frac{{{\ell }^{2}}_{1}}{{{\operatorname{m}}_{1}}}:\frac{{{\ell }^{2}}_{2}}{{{\operatorname{m}}_{3}}}:\frac{{{\ell }^{2}}_{3}}{{{\operatorname{m}}_{3}}}\,\,\,\,\,\,\,\,\,\,\rho =\frac{mass}{volume}\] \[=\frac{{{\left( 5 \right)}^{2}}}{1}:\frac{{{\left( 3 \right)}^{2}}}{3}:\frac{{{\left( 1 \right)}^{2}}}{5}\] \[=25:\frac{9}{3}:\frac{1}{5}\,\,\,\,\operatorname{or}\,\,125:15:1\]


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