A) \[{{\operatorname{F}}_{1}}\left[ 1-\frac{y}{L} \right]+{{\operatorname{F}}_{2}}\left[ \frac{y}{L} \right]\]
B) \[{{\operatorname{F}}_{2}}\left[ 1-\frac{y}{L} \right]+{{\operatorname{F}}_{1}}\left[ \frac{y}{L} \right]\]
C) \[\left( {{\operatorname{F}}_{1}}-{{\operatorname{F}}_{2}} \right)\frac{y}{L}\]
D) None of these
Correct Answer: A
Solution :
\[\operatorname{Net} force on the rod = {{F}_{1}}-{{F}_{2}}\] \[\operatorname{Acceleration} of rod =\frac{{{\operatorname{F}}_{1}}-{{\operatorname{F}}_{2}}}{\operatorname{M}}\] Rod of length 'L' has mass = M \[\operatorname{Rod} of length 'y' has mass =\frac{M}{L}y\] \[{{\operatorname{F}}_{1}}-\operatorname{T}=\frac{M}{L}y.a\] \[{{\operatorname{F}}_{1}}-\operatorname{T}=\frac{M}{L}y\frac{{{\operatorname{F}}_{1}}-{{\operatorname{F}}_{2}}}{\operatorname{M}}\] \[\operatorname{T}={{\operatorname{F}}_{1}}\left[ 1-\frac{y}{L} \right]+{{\operatorname{F}}_{2}}\frac{y}{L}\]You need to login to perform this action.
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