A) \[{{\operatorname{SeO}}_{2}}\]
B) \[{{\operatorname{Al}}_{2}}{{O}_{3}}\]
C) \[{{\operatorname{Sb}}_{2}}{{O}_{3}}\]
D) \[{{\operatorname{Bi}}_{2}}{{O}_{3}}\]
Correct Answer: D
Solution :
\[{{\operatorname{Bi}}_{2}}{{\operatorname{O}}_{3}}\] The size of \[{{\operatorname{Bi}}^{3+}}\]is very large and has very weak +ve field around it. Therefore, it does not interact with H20 to release H+ ions. \[{{\operatorname{Bi}}^{3+}}3H-O-H\to Bi{{\left( OH \right)}_{3}}+{{H}^{+}}\] In contrast 02 is small and has a stronge -ve electric field around it. It, therefore interact with water releasing OH - ions. \[\operatorname{Thus}, B{{i}_{2}}{{O}_{3}} is strong basic oxide.\]You need to login to perform this action.
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