A) \[\operatorname{NaOH}\]
B) \[{{\operatorname{Cl}}_{2}}\]
C) \[{{\operatorname{H}}_{2}}\]
D) \[{{\operatorname{O}}_{2}}\]
Correct Answer: D
Solution :
\[{{\operatorname{O}}_{2}}\] On electrolysis of brine solution, \[\operatorname{Outer} compartments, NaCI\to N{{a}^{+}}+ C{{l}^{-}}\] \[{{\operatorname{H}}_{2}}O being a weak electrolyte\] \[{{\operatorname{H}}_{2}}O\rightleftharpoons {{H}^{+}}+O{{H}^{-}}\] At anode \[{{\operatorname{Cl}}^{-}}\to Cl + {{e}^{-}}, Cl + Cl\to C{{l}_{2}}\uparrow \] At cathode \[{{\operatorname{Na}}^{+}}+ {{e}^{-}} \to Na\] \[2Na+xHg\to \underset{\operatorname{S}\,o\,d. A\,m\,a\,l\,g\,a\,m}{\mathop{N{{a}_{2}}.Hgx}}\,\] Central compartment \[\operatorname{NaOH}\to N{{a}^{+}}+O{{H}^{-}}\] \[{{\operatorname{H}}_{2}}O\rightleftharpoons {{H}^{+}}+O{{H}^{-}}\] At cathode, \[{{\operatorname{H}}^{+}}+{{e}^{-}}\to H; H+H\to {{H}_{2}}\uparrow \] At anode, \[{{\operatorname{OH}}^{-}}\to OH+{{e}^{-}}\] \[{{\operatorname{Na}}_{2}}Hgx + 2OH\to 2NaOH + xHg\]
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