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NEET Sample Paper NEET Sample Test Paper-48

  • question_answer
    The correct order of bond angles/smallest \[\operatorname{first}/\,in {{H}_{2}}S, N{{H}_{3}} B{{F}_{3}} and Si{{H}_{4}}\]is:

    A) \[{{\operatorname{H}}_{2}}S < Si{{H}_{4}} < N{{H}_{3}} < B{{F}_{3}}\]

    B) \[{{\operatorname{NH}}_{3}} < {{H}_{2}}S < SiH{{ }_{4}}< B{{F}_{3}}\]

    C) \[{{\operatorname{H}}_{2}}S < N{{H}_{3}} < Si{{H}_{4}}< B{{F}_{3}}\]

    D) \[{{\operatorname{H}}_{2}}S < N{{H}_{3}}< B{{F}_{3}}< Si{{H}_{4}}\]

    Correct Answer: C

    Solution :

    \[{{\operatorname{H}}_{2}}S < N{{N}_{3}} < Si{{H}_{4}} < B{{F}_{3}}\] Bond angle      compound \[92{}^\circ 6{}^\circ {{H}_{2}}S\] \[107{}^\circ N{{H}_{3}}\] \[10{{9}^{o}}28'Si{{H}_{4}}\] \[120{}^\circ B{{F}_{3}}\]


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