A) Mass
B) Length
C) Time
D) Angle
Correct Answer: D
Solution :
\[\operatorname{E} = M{{L}_{2}}{{T}^{-2}}, J = M{{L}^{2}}{{T}^{-1}}, G = {{M}^{-1}}{{L}^{3}}{{T}^{-2}}\] \[\operatorname{Dimension} =\frac{E{{J}^{2}}}{{{m}^{5}}{{G}^{2}}~}=\frac{M{{L}^{2}}{{T}^{-2}} \left[ M{{L}^{2}}{{T}^{-1}}^{2} \right]}{{{M}^{5}}\left[ {{M}^{-1}}{{L}^{3}}{{T}^{-2}} \right]}\] \[= M{}^\circ L{}^\circ T{}^\circ = Angle\]You need to login to perform this action.
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