A) 50 years
B) 70 years
C) 500 years
D) 700 years
Correct Answer: D
Solution :
70 years \[\operatorname{k}=\frac{0.693}{10}yea{{r}^{-1}}\] \[\operatorname{k}=\frac{2.303}{\operatorname{t}}\log \frac{a}{a-0.99a}\] \[=\frac{2.303}{\operatorname{t}}\log {{10}^{2}}\] \[or\,\,t=\frac{2.303\times 10\times 2}{0.693}\operatorname{form}(1)\] \[= 66.5years 70years\]
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