A) 282.4 kJ
B) 298.3 kJ
C) 290.1 kJ
D) 315.4 kJ
Correct Answer: B
Solution :
\[\underset{g}{\mathop{HI}}\,\to \underset{g}{\mathop{H}}\,~\,\,\,\,\,\,\,\,+~\,\,\,\,\,\,\underset{g}{\mathop{I}}\,~~~~~\,\,\,\Delta G=\text{ }271.8\text{ }kJ\] \[\Delta S=\text{ }206.5\text{ }114.6~~\,\,180.7~~~J\,\,mo{{l}^{-}}^{1}\] \[\Delta S\text{ }=\left( 114.6+180.7 \right)-\left( 206.5 \right)\] \[=\text{ }295.3\,\,-\,\,206.5\] \[\Delta S\,\,=\,\,88.8\text{ }J\text{ }mo{{l}^{-1}}\,{{K}^{-}}^{1}\] \[\Delta G=\Delta H-T\Delta S\] \[=\text{ }271.8\,\,+\,\,298\,\,\times \,\,\frac{88.8}{1000}\,\,=\,\,298.3\text{ }kJ\]You need to login to perform this action.
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