A) \[2.0\times {{10}^{4}}\,N\]
B) \[2.0\times {{10}^{6}}\]
C) \[2.0\times {{10}^{10}}N\]
D) \[2.0\times {{10}^{\text{8}}}\,N\]
Correct Answer: D
Solution :
\[{{q}_{1}}\,=\,\frac{1}{{{10}^{6}}}\times 1.6\times \,{{10}^{-19}}\times \frac{10}{63.5}\,\,\times {{10}^{23}}\,=\,{{q}^{2}}\] \[F=\frac{k{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\]You need to login to perform this action.
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