A) 6.93
B) 3.69
C) 9.63
D) None of these
Correct Answer: B
Solution :
\[\beta =\frac{25}{26}\] \[{{R}_{in}}\,\,=\,\,200\,\Omega \] \[\beta =\frac{{{i}_{C}}}{{{i}_{b}}}\,\,=\,\,\frac{25}{26}\] Here, \[{{I}_{C}}{{R}_{L}}\,\,=\,\,0.8\,V\] \[\therefore \,\,\,{{I}_{C}}\,=\,\,\frac{0.8}{{{R}_{L}}}=\frac{0.8}{800}\,\,=\,\,{{10}^{-3}}\,A\,\,=\,\,1\,\,mA\] Power gain \[=\,\,{{\beta }^{2}}\,\,=\,\,\frac{{{R}_{L}}}{{{R}_{in}}}\,\,=\,\,\left( \frac{25}{26} \right){{\,}^{2}}\,\times \,\frac{800}{200}\,\,=\,\,3.69\]You need to login to perform this action.
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