A) \[\left( {{m}_{1}}-{{m}_{2}} \right)g~\]
B) \[\left( {{m}_{1}}-\text{ }{{m}_{2}} \right)\,\frac{g}{2}\]
C) \[\left( {{m}_{1}}+{{m}_{2}} \right)g\]
D) \[\left( {{m}_{1}}+{{m}_{2}} \right)\,\frac{g}{2}\]
Correct Answer: B
Solution :
\[\,{{F}_{b}}\] = Buoyancy force of air \[{{m}_{1}}:\text{ }{{m}_{1}}g\text{ }=T\,\,+\,\,{{F}_{b}}~~~~~~~~....\left( i \right)\] \[{{m}_{2}}:{{m}_{2}}g\,\,+\,\,T\,\,=\,\,{{F}_{b}}~~~~~~~~....\left( ii \right)\] From eq. (i) & (ii) \[{{m}_{1}}g-T={{m}_{2}}\,g+T\] \[\Rightarrow \,\,\,T\,\,=\,\,\frac{\left( {{m}_{1}}-{{m}_{2}} \right)g}{2}\]You need to login to perform this action.
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