A) \[0.1\,M\]
B) \[0.001M\]
C) \[0.01\text{ }M\]
D) \[\text{1}{{\text{0}}^{-4}}\text{ }M\]
Correct Answer: B
Solution :
Molarity of \[N{{a}_{2}}C{{O}_{3}}\] solution \[=\frac{2.65}{106}\times \frac{1000}{250}=0.1M\] \[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\] \[10\times 0.1=1000\times {{M}_{2}}\] \[{{M}_{2}}=0.001\,M\]You need to login to perform this action.
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