A) \[-{{1.86}^{o}}C\]
B) \[-{{0.186}^{o}}C\]
C) \[-{{0.372}^{o}}C\]
D) \[+{{0.372}^{o}}C\]
Correct Answer: C
Solution :
For \[NaCl,\] \[i=2\] \[\Delta {{T}_{f}}=i\times {{K}_{f}}\times m\] \[=2\times 1.86\times 0.1={{0.372}^{o}}C\] Hence, freezing point of solution \[=0-0.37=-{{0.372}^{o}}C\]You need to login to perform this action.
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