A) \[\frac{2}{3}m\]
B) \[\frac{1}{2}m\]
C) \[\frac{1}{4}m\]
D) \[\frac{1}{6}m\]
Correct Answer: C
Solution :
\[PV=nRT=\frac{m}{M}\,RT\] \[\frac{1}{2}P\times V=\frac{m'}{M}R\times \frac{2}{3}T\] \[PV=\frac{4}{3}\frac{m'}{M}\,RT\] \[\therefore \] \[\frac{m}{M}=\frac{4}{3}\frac{m'}{M}\] \[m'=\frac{3}{4}\,m\] This is the mass left. Hence, mass escaped \[=m-\frac{3}{4}m=\frac{1}{4}m\]You need to login to perform this action.
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