A) \[0.39\,m\,m\]
B) \[0.40\,m\,m\]
C) \[0.53\,m\,m\]
D) \[450\,\mu \]
Correct Answer: A
Solution :
New fringe width is found to be p times decreased because the D is decreased up to \[\frac{D}{\mu }=\beta =\frac{\beta }{\mu }=\frac{0.4}{4/3}=0.3\,mm\]You need to login to perform this action.
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