A) \[C{{H}_{2}}=C{{H}_{2}}\]
B) \[C{{H}_{3}}C{{H}_{2}}-O-C{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\]
D) \[C{{H}_{3}}-C{{H}_{2}}-O-S{{O}_{3}}H\]
Correct Answer: C
Solution :
\[{{C}_{2}}{{H}_{5}}OH\xrightarrow{PB{{r}_{3}}}{{C}_{2}}{{H}_{5}}Br\xrightarrow{Alc.\,KOH}C{{H}_{2}}=C{{H}_{2}}\] \[\xrightarrow{{{H}_{2}}S{{O}_{4}}}C{{H}_{3}}C{{H}_{2}}OS{{O}_{3}}H\] \[\xrightarrow[-{{H}_{2}}S{{O}_{4}}]{{}^{{{H}_{2}}O}/{}_{\Delta }}\underset{ethanol}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\]
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