A) \[{{r}^{2}}\]
B) \[{{r}^{-2}}\]
C) \[{{r}^{4}}\]
D) \[{{r}^{6}}\]
Correct Answer: C
Solution :
As \[m=Vd=\frac{4}{3}\,\pi {{r}^{3}}d\] (Where, d= density and V = volume) \[\Rightarrow \] \[m\propto {{r}^{3}}\] \[F\propto \frac{{{r}^{3}}\times {{r}^{3}}}{{{r}^{2}}}\propto {{r}^{4}}\]You need to login to perform this action.
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