A) \[7:4\]
B) \[7:6\]
C) \[4:7\]
D) \[7:8\]
Correct Answer: B
Solution :
For parallel combination of two rods of equal length and equal area of cross-section. \[K=\frac{{{K}_{1}}+{{K}_{2}}}{2}=\frac{{{K}_{1}}+\frac{4{{K}_{1}}}{3}}{2}\] \[=\frac{7{{K}_{1}}}{6}\] (given, \[{{K}_{1}}/{{K}_{2}}=3/4\]) Hence, \[\frac{K}{{{K}_{1}}}=\frac{7}{6}\]You need to login to perform this action.
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