A) \[6h\]
B) \[12\,h\]
C) \[42\,h\]
D) \[128\,h\]
Correct Answer: B
Solution :
We have, \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{t/T}}\] or \[\frac{1}{64}={{\left( \frac{1}{2} \right)}^{t/T}}\] or \[{{\left( \frac{1}{2} \right)}^{6}}={{\left( \frac{1}{2} \right)}^{t/T}}\] or \[\frac{t}{T}=6\] \[t=6T\] or \[t=6\times 2=12\]You need to login to perform this action.
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