A) \[2\,\pi \sqrt{k}\]
B) \[\frac{2\,\pi }{\sqrt{k}}\]
C) \[2\,\pi \,k\]
D) \[\frac{2\,\pi }{k}\]
Correct Answer: B
Solution :
\[T=2\pi \,\sqrt{\frac{displacement}{acceleration}}\] \[=2\pi \sqrt{\frac{x}{kx}}=\frac{2\pi }{\sqrt{k}}\]You need to login to perform this action.
You will be redirected in
3 sec