A) \[1.59\,g\]
B) \[3.18\,g\]
C) \[6.35\text{ }g\]
D) \[12.70\text{ }g\]
Correct Answer: C
Solution :
From faraday second law: \[\frac{{{m}_{cu}}}{{{m}_{{{H}_{2}}}}}=\frac{{{E}_{cu}}}{{{E}_{{{H}_{2}}}}}\] \[{{m}_{{{H}_{2}}}}=\frac{2}{22.4}\times 2.24=0.2g\] \[\frac{{{m}_{eu}}}{0.2}=\frac{{}^{63.5}/{}_{2}}{1}\] \[{{m}_{Cu}}=\frac{63.5\times 0.2}{2}=63.5\,g\]You need to login to perform this action.
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