A) \[\frac{\overrightarrow{v}}{2}\,\,and\,\,\frac{v}{2}\]
B) \[0\,\,and\,\,\frac{v}{2}\]
C) 0 and 0
D) \[\,\,\,\frac{\overrightarrow{v}}{2}\,\,and\,\,0\]
Correct Answer: B
Solution :
Average velocity = 0 because net displacement of the body is zero. \[Average\,speed\,\,=\,\,\frac{Total\,dis\tan ce\,\,\operatorname{cov}ered}{Time\,\,of\,\,flight}\,=\,\frac{2H{{M}_{\max }}}{2u/g}\]\[\Rightarrow \,\,\,{{v}_{av}}\,=\,\frac{2{{u}^{2}}/2g}{2u/g}\,\,\Rightarrow \,\,{{v}_{av}}\,=\,u/2\] Velocity of projection = v (given) \[\therefore \,\,{{v}_{av}}=v/2\]You need to login to perform this action.
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