A) \[{{\lambda }_{3}}\,\,=\,\,\,{{\lambda }_{1}}\,+\,\,{{\lambda }_{2}}\]
B) \[{{\lambda }_{3}}\,=\,\,\frac{{{\lambda }_{1}}\,{{\lambda }_{2}}}{{{\lambda }_{1}}+\,{{\lambda }_{2}}}\]
C) \[{{\lambda }_{1}}\,+\,\,{{\lambda }_{2}}\,+\,\,{{\lambda }_{3}}\,\,=\,\,0\]
D) \[\lambda _{3}^{2}\,+\,\,\lambda _{1}^{2}\,\,+\,\,\lambda _{2}^{2}\,\]
Correct Answer: B
Solution :
\[{{E}_{3}}={{E}_{1}}+{{E}_{2}}\] \[\frac{hc}{{{\lambda }_{3}}}=\frac{hc}{{{\lambda }_{1}}}+\frac{hc}{{{\lambda }_{2}}}\,\,\,\Rightarrow \,\,\,\frac{1}{{{\lambda }_{3}}}=\frac{1}{{{\lambda }_{1}}}+\frac{1}{{{\lambda }_{2}}}\]You need to login to perform this action.
You will be redirected in
3 sec