A) \[f\]
B) \[f\sqrt{2}\]
C) \[2f\]
D) \[4f\]
Correct Answer: A
Solution :
If l be the length of the wire then frequency \[f=\frac{1}{lD}\,\sqrt{\frac{T}{\pi \rho }}\] When tension T is doubled, density p is halved, diameter D is doubled f would remain the same.You need to login to perform this action.
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