A) 5
B) 4
C) 3
D) 2
Correct Answer: C
Solution :
The complex compound \[\left[ MC{{l}_{2}}B{{r}_{2}} \right]S{{O}_{4}}\] gives \[\left[ MC{{l}_{2}}BrS{{O}_{4}} \right]\] Br as ionisation isomer and also cisisomer, trans-isomers as geometrical isomers.You need to login to perform this action.
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