A) \[\frac{3GM}{{{a}^{2}}}\,,\,\,\frac{3GM}{2a}\]
B) \[-\frac{3G{{M}^{2}}}{a}\,,\,\,\frac{3G{{M}^{2}}}{2a}\]
C) \[-\frac{3G{{M}^{2}}}{{{a}^{2}}}\,,\,\,\frac{3G{{M}^{2}}}{4{{a}^{2}}}\]
D) \[-\frac{3G{{M}^{2}}}{a}\,,\,\,\frac{3GM}{2a}\]
Correct Answer: B
Solution :
\[{{U}_{initial}}\,\,=\,\,3\left( \frac{-G{{M}^{2}}}{a} \right)\] \[{{U}_{final}}\,\,=\,\frac{-3G{{M}^{2}}}{2a}\] \[w=\Delta u={{U}_{f}}-{{U}_{i}}\,=\,\,\frac{3}{2}\,\frac{G{{M}^{2}}}{a}\]You need to login to perform this action.
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