A) \[{{f}_{0}}=45\text{ }cm\text{ }and\text{ }{{f}_{e}}=-9\text{ }cm\]
B) \[{{f}_{0}}=50\text{ }cm\text{ }and\text{ }{{f}_{e}}=10\text{ }cm\]
C) \[{{f}_{0}}=7.2\text{ }cm\text{ }and\,\,{{f}_{e}}=5\,\,cm\]
D) \[{{f}_{0}}=30\text{ }cm\text{ }and\text{ }{{f}_{e}}=6\text{ }cm\]
Correct Answer: D
Solution :
For far point in telescope \[M.P=\left| \frac{{{f}_{0}}}{{{f}_{e}}} \right|=5~~~~~~~.......\left( 1 \right)\] \[L={{f}_{0}}+{{f}_{e}}\,\,=\,\,36\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,.......(2)\] \[\therefore \,\,\text{ }{{f}_{0}}=30\text{ }cm,\text{ }{{f}_{e}}=6\text{ }cm\]You need to login to perform this action.
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