A) 20 kV
B) 41 Kv
C) 52 kV
D) 102 kV
Correct Answer: B
Solution :
\[\frac{hc}{e{{V}_{0}}}\,\,=\,\,\lambda \,and\,\,\frac{hc}{3e{{V}_{0}}}\,=\,\,\lambda -\Delta \lambda \] \[\Rightarrow \,\,{{V}_{0}}\,\,=\,\,\frac{2hc}{3e\Delta \lambda }\,\,=\,\,41\,\,kV\]You need to login to perform this action.
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