A) 8 V
B) -8 V
C) 12 V
D) -12 V
Correct Answer: B
Solution :
By using KVL A to A \[12+\frac{q}{4}-24+\frac{q}{2}\,\,=\,\,0\] \[\frac{q}{2}+\frac{q}{4}\,\,=\,\,12\] \[q=\frac{12\times 4}{3}\,=\,16\,\mu C\] \[{{V}_{A}}-{{V}_{B}}\,\,=\,\,\frac{-q}{2\mu }\,\,=\,\,-8V\]You need to login to perform this action.
You will be redirected in
3 sec