A) 28.5 kJ
B) 17.1 kJ
C) 45.7 kJ
D) 1.7 kJ
Correct Answer: B
Solution :
\[0.3\text{ }mole\text{ }O{{H}^{-}}\text{ }neutralise\text{ }0.3\text{ }mol\text{ }HN{{O}_{3}}\] \[\Delta H=-57.1\times 0.3=-17.13\text{ }kJ\]You need to login to perform this action.
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