A) 3mg
B) 4mg
C) 5 mg
D) 6 mg
Correct Answer: D
Solution :
To complete the circle \[{{v}_{\min }}=\sqrt{5g\ell }\] \[T-mg=\frac{m{{v}^{2}}}{\ell };\] \[T\,\,-\,\,mg\,\,=\,\,5\,mg\] \[T\,\,=\,\,6\,mg\]You need to login to perform this action.
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