A) \[1\text{ }:\text{ }6\]
B) \[1\text{ }:\text{ }12\]
C) \[1\text{ }:\text{ }3\]
D) \[1\text{ }:\text{ }4\]
Correct Answer: B
Solution :
\[\frac{{{m}_{A}}{{C}_{A}}}{{{m}_{B}}{{C}_{B}}}=\frac{(4/3)\pi r_{A}^{3}{{\rho }_{A}}{{C}_{A}}}{(4/3)\pi r_{B}^{3}{{\rho }_{B}}{{C}_{B}}}\] \[=\,\,{{\left( \frac{1}{2} \right)}^{3}}\times \frac{2}{1}\times \frac{1}{3}=\frac{1}{12}\]
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