A) \[9\,m/s\]
B) \[9\sqrt{2}\,m\]
C) \[18\,m/s\]
D) \[18\sqrt{2}\,m/s\]
Correct Answer: C
Solution :
\[\because \,\,\,\,\tan \alpha \,\,=\,\,\frac{{{V}_{y}}}{{{V}_{x}}},\,\,\,\,\,\,\,\,\,\,\,\,1=\frac{{{V}_{y}}}{18}\] \[\therefore \,\,\,\text{ }{{V}_{y}}\,\,=\,\,18\text{ }m/s\]You need to login to perform this action.
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