A) P/2
B) P/3
C) P/4
D) P/6
Correct Answer: A
Solution :
\[{{N}_{2}}+3{{H}_{2}}\,\,\rightleftharpoons \,\,N{{H}_{3}}\] \[t=0\] 1 3 0 \[t=?\] \[1-x\] \[3-3x\] \[2x\] \[nx=a\alpha \] At equi. 1/2 3/2 1 \[1x=\frac{1\times 50}{100}\]\[{{P}_{{{H}_{2}}}}=\frac{\frac{3}{2}}{3}\,\,\times P\] \[x=\frac{1}{2}\] \[{{P}_{{{H}_{2}}}}=\frac{P}{2}\]You need to login to perform this action.
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