A) \[\frac{{{\mu }_{0}}}{2\pi a}({{I}_{1}}+{{I}_{2}})\]
B) \[\frac{{{\mu }_{0}}}{2\pi a}({{I}_{1}}-{{I}_{2}})\]
C) \[\frac{{{\mu }_{0}}}{2\pi a}{{(I_{1}^{2}-I_{2}^{2})}^{1/2}}\]
D) \[\frac{{{\mu }_{0}}}{2\pi a}\frac{{{I}_{1}}{{I}_{2}}}{({{I}_{1}}+{{I}_{2}})}\]
Correct Answer: C
Solution :
\[{{B}_{1}}\,\,=\,\,\frac{{{\mu }_{0}}{{I}_{1}}}{2\pi d}\] \[{{B}_{2}}\,\,=\,\,\frac{{{\mu }_{0}}{{I}_{2}}}{2\pi d}\] \[B=\sqrt{B_{1}^{2}+B_{2}^{2}}\]You need to login to perform this action.
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