A) \[\frac{9p}{32\pi {{\in }_{0}}}\widehat{k}\]
B) \[\frac{-7p}{32\pi {{\in }_{0}}}\widehat{k}\]
C) \[\frac{-9p}{32\pi {{\in }_{0}}}\widehat{k}\]
D) \[\frac{4p}{32\pi {{\in }_{0}}}\widehat{k}\]
Correct Answer: B
Solution :
Due 1st dipole, electric field \[\overrightarrow{{{E}_{1}}}=\,\,\frac{1}{4\pi {{\in }_{0}}}\,\,\frac{p}{{{I}^{3}}}\,(-\widehat{k})\] Due to 2nd, dipole, electric field \[\overrightarrow{{{E}_{2}}}=\,\,\frac{1}{4\pi {{\in }_{0}}}\,\,\frac{2p/2}{{{2}^{3}}}\,\,\,(\widehat{k})\] \[{{\overrightarrow{E}}_{Net}}={{\overrightarrow{E}}_{1}}+{{\overrightarrow{E}}_{2}}\text{ }=\frac{1}{4\pi {{\in }_{0}}}\left( \frac{1}{8}-1 \right)\text{ }\widehat{k}\] \[=\frac{-7p}{32\pi {{\in }_{0}}}\,\,\widehat{k}\]You need to login to perform this action.
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