A) \[{{4}^{2/3}}\]
B) \[{{4}^{1/3}}\]
C) \[{{4}^{-2/3}}\]
D) \[{{4}^{-1/3}}\]
Correct Answer: B
Solution :
\[I=M{{R}^{2}}=\left( 2\pi RAd \right){{R}^{2}}\] \[or\text{ }\,I\,\,\propto \,\,{{R}^{3}}\] \[or\,\,\text{ }R\,\,\propto \,\,{{I}^{1/3}}\] \[or\,\,\,\frac{{{R}_{2}}}{{{R}_{1}}}={{\left( \frac{{{I}_{2}}}{{{I}_{1}}} \right)}^{1/3}}\,\,=\,\,{{\left( \frac{4}{1} \right)}^{1/3}}\]You need to login to perform this action.
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