A) -249 L bar
B) -259 L bar
C) - 239 L bar
D) -220 L bar
Correct Answer: C
Solution :
\[Initial\text{ }volume\text{ }{{V}_{1}}\,\,=\,\,10\,\,L\] \[{{V}_{2}}(final)\,\,=\,\,\frac{nRT}{P}\,\,=\,\,\frac{10\times 0.083\times 300}{1}\,\,=\,\,249\,L\] \[w=-P\Delta Y=-1\left( 249-10 \right)=-239\text{ }L\text{ }bar\]You need to login to perform this action.
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