NEET Sample Paper NEET Sample Test Paper-54

  • question_answer
    The moment of inertia of sphere is \[20\text{ }kg-{{m}^{2}}\] about the diameter. The moment of inertia about any tangent will be-

    A) \[70\text{ }kg-{{m}^{2}}\]                   

    B) \[35\text{ }kg-{{m}^{2}}\]

    C) \[50\text{ }kg-{{m}^{2}}\]                   

    D) \[20\text{ }kg-{{m}^{2}}\]

    Correct Answer: A

    Solution :

    According to the theorem of parallel axes, the have \[\,I={{I}_{G}}\,+\,\,M{{a}^{2}}\,=\,\,\frac{2}{5}\,M{{R}^{2}}\,\,+\,\,M{{R}^{2}}\,\,\,\,\,\,\,\,(\because \,\,a=R)\] \[=\,\,\frac{7}{5}\,M{{R}^{2}}\] Given that \[\frac{2}{5}\,\,M{{R}^{2}}=20\] \[or\,\,M{{R}^{2}}\,\,=\,\,\frac{20\times 5}{2}\,\,=\,\,50\] \[\therefore \,\,\,\,I=\frac{7}{5}\,\,\times \,\,50\,\,=\,\,70\,kg-{{m}^{2}}\]


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