A) \[\frac{{{E}^{2}}}{2V{{B}^{2}}}\]
B) \[\frac{{{B}^{2}}}{2V{{B}^{2}}}\]
C) \[\frac{2V{{B}^{2}}}{{{E}^{2}}}\]
D) \[\frac{2V{{E}^{2}}}{{{B}^{2}}}\]
Correct Answer: A
Solution :
\[qvB\,\,=\,\,qE\,\,\,\Rightarrow \,\,v=\,\,\frac{E}{B}\] But \[\frac{1}{2}m{{v}^{2}}=qV\] \[\frac{q}{m}=\frac{{{v}^{2}}}{2V}=\frac{{{E}^{2}}}{2V{{B}^{2}}}\]You need to login to perform this action.
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