A) \[2HI+{{H}_{2}}{{O}_{2}}\to \,\,{{I}_{2}}\,\,+\,\,2{{H}_{2}}O\]
B) \[FeS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}+{{H}_{2}}{{O}_{2}}\to \,\,\,F{{e}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}+2{{H}_{2}}O\]
C) \[MnO+{{H}_{2}}{{O}_{2}}\,\,\to \,\,Mn{{O}_{2}}+{{H}_{2}}O\]
D) \[{{\text{I}}_{\text{2}}}+2NaOH\,\,+\,\,{{H}_{2}}{{O}_{2}}\to 2NaI+{{H}_{2}}O+{{O}_{2}}\]
Correct Answer: D
Solution :
\[{{H}_{2}}{{O}_{2}}\] act as a both O.A & R.A \[{{H}_{2}}\overset{-1}{\mathop{{{O}_{2}}}}\,\text{ }\to \,\,{{\text{H}}_{\text{2}}}\overset{-2}{\mathop{\text{O}}}\,\,\,\text{+}\,\,\frac{1}{2}\,\,{{\overset{0}{\mathop{O}}\,}_{2}}\]
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