A) n-type and its resistivity is \[0.34\,\Omega -m\]
B) p-type and its resistivity is \[0.034\,\Omega -m\]
C) n-type and its resistivity is \[0.034\,\Omega -m\]
D) p-type and its resistivity is \[3.4\,\,\Omega -m\]
Correct Answer: A
Solution :
\[{{n}_{e}}>>>{{n}_{h}}\] \[\therefore \] N type semiconductor \[\rho =\frac{1}{e[{{\mu }_{h}}{{n}_{h}}+{{\mu }_{e}}{{n}_{e}}]}\] \[=\,\,\frac{1}{1.6\times {{10}^{-19}}\left[ 2.3\times 8\times {{10}^{18}}+0.01\times 5\times {{10}^{18}} \right]}\] \[=\,\,\frac{1}{0.16\left[ 18.4+0.05 \right]}\,\,=\,\,\frac{1}{0.16\times 18.45}\] \[=\,\,\frac{1}{520}\,\,=\,\,0.34\,\Omega -m\]You need to login to perform this action.
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