A) \[1\,\,:\,\,\sqrt{3}\]
B) \[\sqrt{3}\,\,:\,\,1\,\,\]
C) \[1\,\,:\,\,1\,\,\]
D) \[1\,\,:\,\,2\,\,\]
Correct Answer: A
Solution :
\[{{H}_{1}}={{H}_{2}}\] \[H=\frac{{{u}^{2}}{{\sin }^{2}}\,\theta }{2g}\] \[u\propto \frac{1}{\sin \,\theta }\] \[\frac{{{u}_{1}}}{{{u}_{2}}}=\frac{\sin \,{{\theta }_{2}}}{\sin \,{{\theta }_{1}}}\,\,\Rightarrow \,\,\frac{\sin \,30}{\sin \,60}\,\,=\,\,(1\,\,:\,\,\sqrt{3})\]You need to login to perform this action.
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